先将根号3分之1分母有理化即为3分之根号3再将根号3提出即为√3（1+1/3）=4√3/3
√3+√(1/3)=√3+√3/3=4√3/3
解：原式=√(9*1/3)+√(1/3)=3√(1/3)+√(1/3)=4√(1/3)
