y=(1-x^2)^n的微分

2025-12-15 04:16:53
推荐回答(1个)
回答1:

y=(1-x^2)^n
dy
=n(1-x^2)^(n-1) d(1-x^2)
=n(1-x^2)^(n-1) (-2x dx)
=-2nx.(1-x^2)^(n-1) dx